(7a+2)(2a^2-5a-7)=0

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Solution for (7a+2)(2a^2-5a-7)=0 equation:


Simplifying
(7a + 2)(2a2 + -5a + -7) = 0

Reorder the terms:
(2 + 7a)(2a2 + -5a + -7) = 0

Reorder the terms:
(2 + 7a)(-7 + -5a + 2a2) = 0

Multiply (2 + 7a) * (-7 + -5a + 2a2)
(2(-7 + -5a + 2a2) + 7a * (-7 + -5a + 2a2)) = 0
((-7 * 2 + -5a * 2 + 2a2 * 2) + 7a * (-7 + -5a + 2a2)) = 0
((-14 + -10a + 4a2) + 7a * (-7 + -5a + 2a2)) = 0
(-14 + -10a + 4a2 + (-7 * 7a + -5a * 7a + 2a2 * 7a)) = 0
(-14 + -10a + 4a2 + (-49a + -35a2 + 14a3)) = 0

Reorder the terms:
(-14 + -10a + -49a + 4a2 + -35a2 + 14a3) = 0

Combine like terms: -10a + -49a = -59a
(-14 + -59a + 4a2 + -35a2 + 14a3) = 0

Combine like terms: 4a2 + -35a2 = -31a2
(-14 + -59a + -31a2 + 14a3) = 0

Solving
-14 + -59a + -31a2 + 14a3 = 0

Solving for variable 'a'.

The solution to this equation could not be determined.

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